Hello students! Are you preparing for your UP Board Exam 2026 and searching for high-quality, English-medium study materials? Solving previous years' question papers is one of the most effective ways to score top marks. Many students search for Class 10 Science Important Questions UP Board but struggle to find complete, accurate translations of the actual board papers.
To aid your preparation, we have fully solved two crucial past papers: UP Board Class 10 Science Solved Paper 2022 Set 824 BJ and Set 824 BP English Medium. These detailed solutions will prove invaluable for your revision. This comprehensive guide provides step-by-step answers to Science paper sets 824 (BJ) and 824 (BP), covering critical Physics numericals, chemical reactions in Chemistry, and important Biology diagrams.
By thoroughly reviewing these fully solved UP Board 10th Science Paper Sets 824 (BJ) and 824 (BP), you will understand the exam pattern, frequently asked concepts, and how to structure your answers for maximum marks. Let's begin our revision!
Science Paper Code: 824 (BJ) - 2022
PART - A (Physics)
👁️ View Answer
Ans: (ii) DiamondExplanation: Diamond has the highest optical density among the given options, resulting in the highest refractive index (approximately 2.42). This means light travels slowest in diamond compared to the others.
👁️ View Answer
Ans: (i) Concave lensExplanation: In myopia, the image of a distant object is formed in front of the retina. A concave (diverging) lens spreads out the light rays before they enter the eye, pushing the focal point back onto the retina.
👁️ View Answer
Ans: (iii) Never intersect each otherExplanation: If two magnetic field lines intersected, it would mean that at the point of intersection, the magnetic field has two different directions, which is physically impossible.
👁️ View Answer
Ans: (i) \( B = \Phi/A \)Explanation: Magnetic flux (\( \Phi \)) through an area \( A \) perpendicular to a uniform magnetic field \( B \) is defined as the product of the magnetic field and the area: \( \Phi = B \times A \). Rearranging this gives \( B = \Phi / A \).
Solution:
For a concave mirror, if the image forms at the same position as the object, it means the object is placed precisely at the Center of Curvature (\(C\)).
Object distance (\( u \)) = \( -30 \text{ cm} \)
Image distance (\( v \)) = \( -30 \text{ cm} \) (since it forms on the object)
Using the mirror formula: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \]
Answer: The focal length of the concave mirror is 15 cm.
Solution:
The relationship between the radius of curvature (\( R \)) and the focal length (\( f \)) of a spherical mirror is given by the formula \( R = 2f \).
Radius of curvature (\( R \)) = \( 2 \times 40 \text{ cm} = 80 \text{ cm} \)
Answer: The radius of curvature is 80 cm.
Solution:
Convex mirrors are used as rear-view mirrors in vehicles primarily for two reasons:
- They always produce an erect (upright) and diminished (smaller) image of the objects behind the vehicle, regardless of their distance. This prevents the image from appearing upside down.
- Because their reflecting surface is curved outwards, they offer a much wider field of view compared to plane mirrors. This allows the driver to see a much larger area of the traffic behind them, improving safety.
Solution:
Mass of electron (\( m \)) = \( 9 \times 10^{-31} \text{ kg} \)
Charge of electron (\( q \)) = \( 1.6 \times 10^{-19} \text{ C} \)
Velocity (\( v \)) = \( 3 \times 10^6 \text{ m/s} \) (along X-axis)
Magnetic field (\( B \)) = \( 0.3 \text{ Wb/m}^2 \) (along Z-axis)
Since velocity and magnetic field are mutually perpendicular, angle \( \theta = 90^\circ \)
1. Magnetic Force (\( F \)):
2. Acceleration (\( a \)):
3. Direction of Force: According to Fleming's Left-Hand Rule, since the electron (negative charge) is moving along the positive X-axis, the direction of conventional current is along the negative X-axis. The magnetic field is along the Z-axis. Therefore, the force will act along the Y-axis (positive Y-axis).
Solution:
Magnetic Effect of Electric Current: When an electric current flows through a conducting wire, it produces a magnetic field in the space surrounding the wire. This phenomenon, discovered by Hans Christian Oersted, is known as the magnetic effect of electric current. The wire behaves like a temporary magnet as long as the current is flowing.
Factors affecting the Magnetic Field Intensity (\( B \)) of a straight conductor:
The intensity of the magnetic field produced at a point near a long straight current-carrying conductor depends on two main factors:
- Magnitude of the Current (\( I \)): The magnetic field is directly proportional to the current flowing through the wire (\( B \propto I \)). A stronger current produces a stronger magnetic field.
- Distance from the Wire (\( r \)): The magnetic field is inversely proportional to the perpendicular distance from the wire (\( B \propto 1/r \)). The field is strongest near the wire and weakens as you move further away.
Rule for Direction: Right-Hand Thumb Rule (Maxwell's Corkscrew Rule)
The direction of the magnetic field lines around a straight conductor is given by the Right-Hand Thumb Rule.
Rule: Imagine holding the current-carrying straight conductor in your right hand such that the thumb points in the direction of the electric current. Then, the direction in which your fingers curl around the conductor gives the direction of the magnetic field lines.
PART - B (Chemistry)
👁️ View Answer
Ans: (ii) \( \text{C}_3\text{H}_8 \)Explanation: Propane is an alkane, which follows the general formula \( \text{C}_n\text{H}_{2n+2} \). The prefix 'prop' indicates 3 carbon atoms. Substituting \( n = 3 \), we get \( \text{C}_3\text{H}_{2(3)+2} = \text{C}_3\text{H}_8 \).
(i) \( \text{CH}_3\text{COOH} + \text{C}_2\text{H}_5\text{OH} \xrightarrow{\text{Conc. H}_2\text{SO}_4} \dots \)
(ii) \( \text{C}_2\text{H}_5\text{Br} + \text{KOH (aq)} \rightarrow \dots \)
Solution:
(i) This is an Esterification reaction. Acetic acid and ethyl alcohol react in the presence of concentrated sulfuric acid to form 'ethyl acetate' (an ester) which has a sweet, fruity smell.
(ii) This is a Substitution reaction. When ethyl bromide is treated with aqueous potassium hydroxide, the bromine atom is substituted by the OH group, forming ethanol.
PART - C (Biology)
👁️ View Answer
Ans: (i) RespirationExplanation: Hemoglobin is a red respiratory pigment found in red blood cells (RBCs). Its primary function is to bind with oxygen (\( \text{O}_2 \)) in the lungs and transport it to all the cells of the body for cellular respiration.
Solution:
In humans and other mammals, blood passes through the heart twice during one complete cycle through the body. This is known as Double Circulation. This system is highly efficient as it strictly separates oxygen-rich (oxygenated) and oxygen-poor (deoxygenated) blood. It consists of two main pathways:
- Pulmonary Circulation: In this pathway, deoxygenated blood from the body enters the right ventricle and is pumped via the pulmonary artery to the lungs. In the lungs, the blood absorbs oxygen and releases carbon dioxide. The newly oxygenated blood then returns to the left atrium of the heart via pulmonary veins.
- Systemic Circulation: The oxygenated blood from the left atrium enters the left ventricle. From here, it is forcefully pumped through the aorta to all organs and tissues of the body (except lungs). After the tissues utilize the oxygen, the deoxygenated blood is collected by the vena cava and returned to the right atrium of the heart.
This type of circulation ensures a steady and sufficient supply of oxygen to meet the high energy demands of mammals.
Science Paper Code: 824 (BP) - 2022
PART - A (Physics)
Solution:
Potential difference (\( V \)) = \( 1.5 \text{ V} \)
Electric current (\( I \)) = \( 0.5 \text{ A} \)
Length of wire (\( l \)) = \( 3 \text{ m} \)
Cross-sectional area (\( A \)) = \( 6 \times 10^{-6} \text{ m}^2 \)
Resistivity (\( \rho \)) = ?
First, calculate the resistance (\( R \)) of the wire using Ohm's Law:
Now, use the formula for resistivity: \[ R = \rho \frac{l}{A} \]
Solving for \( \rho \):
Answer: The resistivity of the material of the wire is \( 6 \times 10^{-6}\ \Omega \cdot \text{m} \).
Solution:
1. Resistance of each bulb: (Using formula \( P = \frac{V^2}{R} \Rightarrow R = \frac{V^2}{P} \))
Resistance of second bulb (60W), \( R_2 = \frac{(220)^2}{60} = \frac{48400}{60} \approx \mathbf{806.67\ \Omega} \)
2. Separate current drawn by each bulb: (Using formula \( I = \frac{P}{V} \))
Current drawn by second bulb, \( I_2 = \frac{60}{220} \approx \mathbf{0.27 \text{ A}} \)
3. Total current drawn from the electric mains: (In parallel, total current is the sum of individual currents)
4. Equivalent Resistance: (Using Ohm's law \( R_{eq} = \frac{V}{I} \))
PART - B (Chemistry)
Solution:
i) Reaction of acetic acid with sodium hydroxide (base) - Neutralization:
ii) Reaction of ethanol with sodium metal:
iii) Esterification reaction:
iv) Oxidation of ethanol (\(\text{KMnO}_4\) is a strong oxidizing agent):
v) Dehydration of ethanol (at \( 170^\circ\text{C} \)):
PART - C (Biology)
👁️ View Answer
Ans: (ii) PlacentaExplanation: During pregnancy, a special disc-like tissue called the placenta develops between the embryo and the uterine wall of the mother. It is through the placenta that the embryo receives oxygen and essential nutrients from the mother's blood, and waste products are transferred back into the mother's blood for excretion.
Solution:
The human male reproductive system is primarily located in the pelvis region. Its main organs include:
- Testis: The primary reproductive organ where sperms (male gametes) and the hormone testosterone are produced.
- Scrotum: A pouch of skin that holds the testes outside the abdominal cavity to maintain a lower temperature necessary for sperm production.
- Vas deferens: A tube that transports mature sperms from the epididymis to the urethra.
- Prostate gland and Seminal Vesicles: These glands secrete fluids that mix with sperms to form semen. This fluid provides nutrition and mobility to the sperms.
- Penis: The copulatory organ that serves as a common passage for both urine and semen to exit the body.
Conclusion
Dear students, this detailed solution guide for the UP Board Class 10 Science Solved Paper 2022 Sets 824 (BJ) and 824 (BP) will provide a new direction to your preparation. Practice writing the physics formulas, chemistry equations, and biology diagrams repeatedly. Wishing you the very best for your board exams!
Frequently Asked Questions (FAQs)
Q1. Will these exact questions be repeated in the 2026 board exam?
Ans: While questions are rarely copy-pasted exactly, the UP Board frequently repeats core concepts and patterns. Solving these papers will give you a solid grasp of 70-80% of the important topics likely to appear.
Q2. What should I keep in mind while solving numerical problems?
Ans: Always start by writing 'Given' values, then write the correct 'Formula', substitute the values, and most importantly, remember to write the final 'Unit' (like Ohm, Ampere, Volt). This ensures you get full marks for step marking.
